Solution:
Minimum number of rotation that Dr cheeks tries to run on his wheel each week = 45
1 Week ≥ 45
Number of rotation already ran by Dr cheek = 6 rotation
It is not given that whether these rotations have to complete at which duration of time.
Supposing that Dr. cheek has done 6 rotations on first day of week.
Let number of rotation done on each day = x
Number of days in a week = 7
→ 6 x + 6 ≥ 45
→ 6 x ≥ 45 -6
→ 6 x ≥ 39
→→ x≥
→→x≥
=7 rotation (Approx) each day