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The thickness of a 6.00 cm square piece of Al that has a mass of .842 g and a density of 2.70 g/cm^3

The thickness of a 6.00 cm square piece of Al that has a mass of .842 g and a density-example-1
User Tomo
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1 Answer

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Volume = Mass / Density
Volume = .842 / 2.70
Volume = .31185 cubic centimeters
Aluminum square * depth = .31185 cubic centimeters
6 * 6 * depth = .31185 cubic centimeters
depth = (.31185 cubic centimeters) / 36
depth = 0.0086625514 centimeters

(That must be aluminum foil.)







User Artur Siepietowski
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