Question

Pleaseeee help!! fast

The volume of oxygen gas at 25oC is 10 m3. If the volume of the gas is doubled, what is its new temperature in oC?

15 points

Answer 1

The new temperature(T₂) : T₂=596 K = 323 °C

Further explanation

Given

T₁ = 25 C + 273 = 298 K

V₁ = 10 m³

V₂ = 20 m³(doubled)

Required

The new temperature(T₂)

Solution

Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature

`\tt (V_1)/(T_1)=(V_2)/(T_2)`

Input the value :

T₂=(V₂.T₁)/V₁

T₂=(20.298)/10

T₂=596 K = 323 °C