Question

Please show me how to solve this step by step im really confused

Answer 1

Given

`-16t^2+v_0t+h_0`

initial velocity = 60 feet per second

initial height = 95 feet

Find

Maximum height attained by the ball

Step-by-step explanation

we have given

`\begin{gathered} h(t)=-16t^2+60t+95 \\ h^(\prime)(t)=-32t+60 \end{gathered}`

put h'(t) = 0

`\begin{gathered} -32t+60=0 \\ -32t=-60 \\ t=(60)/(32)=1.875sec \end{gathered}`

to find the maximum height find the value of h(1.875)

`\begin{gathered} h(1.875)=-16(1.875)^2+60(1.875)+95 \\ h(1.875)=-56.25+112.5+95 \\ h(1.875)=-56.25+207.5 \\ h(1.875)=151.25 \end{gathered}`

Final Answer

Therefore , the maximum height attained by the ball is 151.25 feet