Question

Please answer!

If the thermal energy of the system increases by 600 jewels and 1400 J of heat were added to the system how much work did the system do

600J

800J

1,400J

2,000J

Answer 1

THE ANSWER IS DOWN BELOW :)

Step-by-step explanation:

Answer 2

Answer: The work done by the system is 800 Joules.

Step-by-step explanation:

Internal change in thermal energy of the system,
`\Delta U`= 600 Joules

Energy added to the system the system,Q = 1400 Joules

Work done by the system can be calculated by using First law of thermodynamics:'

`\Delta U=Q-W` (First law of thermodynamics)

`600 J=1400 J-W`

`W=Q-\Delta U=1400 J-600 J=800 J`

The work done by the system is 800 Joules.