Question

Write g(x) = 4x2 + 88x in vertex form.

Answer 1

4 & -484

Explanation:

Answer 2

The vertex form of a quadratic function is given by
`y = a(x - h)^2 + k` , where (h, k) is the vertex of the parabola.

Given the function :

g(x) =
`4x^2+88x`

g(x) =
`4(x^2+22x)`

Now, we will be completing the square ;

g(x) =
`4(x^2+22x+11^2-11^2)` =
`4(x^2+88x+11^2)-4 \cdot(11^2)`

⇒ g(x) =
`4 (x+11)^2 -4 \cdot 121` or

`g(x) =4(x+11)^2 - 484`

therefore, the given function is in the vertex form is,
`g(x) =4(x+11)^2 +(-484)`