Let the number of Go-go scooter to be produced be x and that of Whip scooter y, then
Maximize: R = 3200x + 5000y
subject to:
x + y ≤ 120
3x + 6y ≤ 600
The corner points of the constraints are (0, 0), (0, 100), (40, 80), (120, 0)
For (0, 0): R = 0
For (0, 100): R = 3200(0) + 5000(100) = 500,000
For (40, 80): R = 3200(40) + 5000(80) = 528,000
For (120, 0): R = 3200(120) + 5000(0) = 384,000
Therefore, for maximum revenue, they should produce 40 Go-go scooters and 80 Whip scooters.