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Help for this question pls :)

Help for this question pls :)-example-1

2 Answers

3 votes

Answer:

tan(
(A)/(2) ) = ±
(1)/(5)

Explanation:

Using the trigonometric identity

tan (
(A)/(2) ) = ±
\sqrt{(1-cosA)/(1+cosA) }

Given

tanA =
(5)/(12) =
(opposite)/(adjacent)

This is a right triangle 5- 12- 13 ( with hypotenuse 13 ), then

cosA =
(adjacent)/(hypotenuse) =
(12)/(13) , then

tan (
(A)/(2) )

= ±
\sqrt{(1-(12)/(13) )/(1+(12)/(13) ) }

= ±
\sqrt{((1)/(13) )/((25)/(13) ) }

= ±
\sqrt{(1)/(25) }

= ±
(1)/(5)

User Dan Newton
by
7.6k points
2 votes

Explanation:

tan(A/2)

tan(A/2)=sinA/1+cos A

tan(A/2)= 5/13÷1+12/13

tanA/2=1/5

User Fourpastmidnight
by
8.4k points

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