Question

asked Sep 21, 2018 79.4k views

2 Answers

Alejadro Xalabarder · Answer 1 · 2018-09-26T09:32:57+0000

Answer

612 π m³

1922 m³

The body of the rocket is a cylinder; to find its volume, we are going to use the formula for the volume of a cylinder:

$V=\pi r^2h$

where

is the radius of the cylinder

is the height

We know from our problem that the radius of the cylinder is 6 m and its height is 16 m, so let's replace the values:

$V=\pi (6m)^2(16m)$

$V=\pi (36m^2)(16m)$

$V=576\pi m^3$

V=1809m^3

The volume of the cylinder is
1810m^3

To find the volume of the cone, we are going to use the formula:

$V=\pi r^2(h)/(3)$

where

is the radius

is the height

We know form our problem that the radius of the cone is 6 m and its height is 3 m, so let't replace the values:

$V=\pi (6m)^2((3m)/(3) )$

$V=\pi (36m^2)(1m)$

$V=36\pi m^3$

V=113m^3

Now, we just need to add the volumes in terms of
$\pi$ and the volumes rounded to the nearest whole:

Volume of the item in terms of π =
$576\pi m^3+36\pi m^3=612\pi m^3$

Volume of the item rounded =
1809m^3+113m^3=1922m^3