Question

If you, a physics student, weigh about 70 kg, are standing on the surface of 1

the Moon, who's mass is 7.34 x 10^22 kg what is the force of gravity acting
on the Moon and yourself? The radius of the Moon is 1.71 x 10^6 m.
25 units
400 units
117 N
200 N

Answer 1

Using Newton's universal law of gravitation and the provided values, the force of gravity acting on a person with a mass of 70 kg standing on the surface of the Moon is calculated to be approximately 117 N.

Step-by-step explanation:

To calculate the force of gravity acting on a person standing on the surface of the Moon, we can use Newton's universal law of gravitation, which states that the force of gravity (F) is equal to the gravitational constant (G) times the mass of one object (m1) times the mass of the second object (m2), all divided by the square of the distance between the centers of the two objects (r^2). The formula is represented as F = G * m1 * m2 / r^2.

The gravitational constant (G) is 6.674 x 10^-11 N(m/kg)^2, the mass of the person (m1) is 70 kg, the mass of the Moon (m2) is 7.34 x 10^22 kg, and the radius of the Moon (r) is 1.71 x 10^6 m. Plugging these values into the formula, we get:

F = (6.674 x 10^-11 N(m/kg)^2) * (70 kg) * (7.34 x 10^22 kg) / (1.71 x 10^6 m)^2

Calculating this, the force of gravity on the person on the Moon's surface is approximately 117 N.

Answer 2

it's answer is 117 N

F = Gm1m2/r^2

F = 6.67 * 10 ^-11 * 70 * 7.34 * 10 ^22/(1.71 * 10 ^6)^2

F = 117 N

hope it helps you