Answer:
1) Mass of Egg Chamber → 35 g = 35 g × 1 kg/(1000 g) = 0.035 kg
2) Average Mass of Grade A Egg → 56.7 g = 0.056 kg
3) Calculated Mass
Drop Chamber + Egg → (35 + 56.7) g = 91.7 g = 91.7 g × 1 kg/(1000 g) = 0.0917 kg
4) Time of Drop → 1.5 seconds
5) Maximum Velocity of Drop Chamber (v = g·t) → v = 9.8 m/s² × 1.5 s = 14.7 m/s
6) Maximum Momentum of Drop Chamber
(P = m·v) (right before hitting the ground) → p = 0.0917 kg × 14.7 m/s = 1.34799 kg·m/s
7) Final End Momentum of Drop Chamber → After landing, velocity v = 0 m/s
(p = m·v after landing)
∴ p = m·v = m × 0 m/s = 0 kg·m/s
8) Impulse on Impact →
(0 - 1.34799) kg·m/s = 1.34799 kg·m/s
(Δm·v = Final - Initial)
9) Force on Impact
→ F·t = Δm·v = 1.34799 N·s
(F·t = Δm·v)
Step-by-step explanation: