Question

Graph the six terms of a finite sequence where a1=5 and r=1.25

Answer 1

`\bf n^(th)\textit{ term of a geometric sequence} \\\\ a_n=a_1\cdot r^(n-1)\qquad \begin{cases} a_1=\textit{first term}\\ n=n^(th)\ term\\ r=\textit{common ratio} \end{cases}`


`\bf -----------------------------\\ \begin{array}{ccllll} term&value\\ x&y\\ \textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\ 1&5\cdot (1.25)^(1-1)\\ 2&5\cdot (1.25)^(2-1)\\ 3&5\cdot (1.25)^(3-1)\\ 4&5\cdot (1.25)^(4-1)\\ 5&5\cdot (1.25)^(5-1)\\ 6&5\cdot (1.25)^(6-1)\\ \end{array}`

Answer 2

Answer:Given below

Explanation:

Given

a=5

common ratio(r)=1.25

therefore next term is
`ar,ar^2.......`

`a_2=ar=5* 1.25=6.25`

`a_3=ar^2=5* 1.25^2=7.8125`

`a_4=ar^3=5* 1.25^3=9.765`

`a_5=ar^4=5* 1.25^4=12.207`

`a_6=ar^5=5* 1.25^5=15.258`