Question

What is the equation of the line (in point-slope form) that is parallel to y+2=−7(x+3) and passes through the point (1,4)?

y+1=−7(x−4)
y+4=7(x+1)
y−1=−7(x+4)
y−4=−7(x−1)
y−4=7(x−1)

Answer 1

y−4=−7(x−1)

Explanation:

The point-slope form of the equation for a line with slope m through point (h, k) is ...

y -k = m(x -h)

Your given line has a slope of -7. The parallel line will have the same slope.

So, you want to fill in the above form with m=-7, (h, k) = (1, 4):

y -4 = -7(x -1)