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Evaluate: [5(2-6)+3(8÷4)^2]^2
asked
Nov 24, 2018
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Evaluate: [5(2-6)+3(8÷4)^2]^2
Mathematics
high-school
Igoris
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order of operations
pemdas
parentahsees
exponents
mulitply or divide
add or subtract
for parenthasees, work inside to out, left to right
so
first one is (2-6) which is equal to -4
next parenthaees is (8/4) which is 2
now we got
[5(-4)+3(2)^2]^2
exponent
2^2=4
now we got
[5(-4)+3(4)]^2
mulitply
5(-4)=-20
3(4)=12
now we got
[-20+12]^2
simplify
-20+12=-8
now we got
[-8]^2
64
KDoyle
answered
Nov 26, 2018
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KDoyle
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The answer you're looking for will be,
ANSWER: 64.
Steps:
To get this answer, follow the
PEMDAS
order of operations.
PEMDAS: Parenthesis, Exponents, Multiply, Divide, Add, Subtract.
(IN ORDER IF POSSIBLE)
I hoped this helped, you're welcome :)
Donnica
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Nov 30, 2018
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Donnica
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