Question

I would appreciate if someone would help me

Answer 1

• Smallest Integer = 12

Explanation:

According to question ,

• First Integer → x

• Second Integer → x + 1

• Third Integer → x + 2

Now question says that the sum of the first and twice the second is 80 minus three times the third that means ,

→ x + 2 ( x + 1 ) = 80 - 3 ( x + 2 )

→ x + 2x + 2 = 80 - 3x - 6

→ 3x + 2 = -3x + 74

→ 3x + 3x = 74 - 2

→ 6x = 72

→ x = 72/6

→ x = 12

Hence , value of x is 12 that means :

→ x = First Integer = 12

→ x + 1 = Second Integer = 13

→ x + 2 = Third Integer = 14

In all of these x is the smallest integer and hence 12 is the correct answer .

Answer 2

x = 12

Explanation:

We know that the integers are consecutive. This means that they can be written as:

x, x + 1, and x+2.

First Integer: x

Second Integer: x + 1

Third Integer: x + 2

It is also given that the sum of the first integer and twice the second is 80 minus three times the third.

Write as an equation:

First Integer + 2(Second Integer) = 80 - 3(Third Integer)

Substitute:

x + 2(x+1) = 80 - 3(x+2)

Multiply:

x + 2x + 2 = 80 - 3x - 6

Simplify:

3x + 2 = 74 - 3x

Add 3x to both sides of the equation:

6x + 2 = 74

Subtract 2 from both sides of the equation:

6x = 72

Divide both sides of the equation by 6:

x = 12

Let me know if you have any questions about my explanation!