What is the equation of the quadratic graph with a focus of (1,1) and a directrix of y=-1

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asked Jun 5, 2018 36.3k views

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Chula · Answer 1 · 2018-06-11T23:25:39+0000

Ok the vertex is the midpoint of the line between the focus and directrix so it is (1, 0) and the constant before is equal to 1/4 I believe so the equation should be y= 1/4 * (x-1)^2

What is the equation of the quadratic graph with a focus of (1,1) and a directrix of y=-1

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