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What is the equation of the quadratic graph with a focus of (1,1) and a directrix of y=-1
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What is the equation of the quadratic graph with a focus of (1,1) and a directrix of y=-1

User Rafrsr
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Ok the vertex is the midpoint of the line between the focus and directrix so it is (1, 0) and the constant before is equal to 1/4 I believe so the equation should be y= 1/4 * (x-1)^2
User Chula
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