Question

5.Solve the system using substitution.

y-2x=3
3x-2y=5
A.(-1/2,2)
B.(2,7)
C.(-8,-13)
D.(-11,-19)

Answer 1

OK first convert one of the equations into Y=MX+b form

Y-2x = 3
Add 2X

Y = 2x +3
Now substitute this equation in the other one.
So it would be

3X - 2Y = 5

3X-2(2x+3) = 5

Now solve for y

3X - 4X - 6 = 5

-1X - 6 = 5

Add 6

-1X = 11

X = -11

Now substitute this into one of the equations

Y - 2X = 3

Y -2(-11) = 3

Y +22 = 3

y = 3-22

y = -19