Question

Moving a charge from point A, where the potential is 369.53 V, to point B, where the potential is 217.85 V, takes 0.55 milliJ of work. What is the value of the charge, in micro-Coulombs?

Answer 1

Given:

The potential of point A is

`V_A=369.53\text{ V}`

The potential of point B is

`V_B=\text{ 217.85 V}`

The work done is W = 0.55 milli Joule.

To find the value of charge in micro Coulomb.

Step-by-step explanation:

The charge can be calculated as

`\begin{gathered} Q=(W)/(V_B-V_A) \\ =\frac{0.55*10^3\text{ J}}{217.85-369.53} \\ =-3.63\text{ C} \\ =\text{ -3.63 C}*\frac{10^6\text{ }\mu C}{1\text{ C}} \\ =-3.63*10^6\text{ }\mu C\text{ } \end{gathered}`