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What are the limiting and excess reactants when 26.62 moles of FeS2 react with 59.44 moles of O2

What are the limiting and excess reactants when 26.62 moles of FeS2 react with 59.44 moles-example-1
User Mohammed Li
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1 Answer

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25 votes

Step 1

The reaction must be completed and balanced as follows:

4 FeS2 + 11 O2 => 2 Fe2O3 + 8 SO2

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Step 2

Information provided:

26.62 moles of FeS2

59.44 moles of O2

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Step 3

The limiting and the excess reactant

Procedure: by stoichiometry,

4 FeS2 + 11 O2 => 2 Fe2O3 + 8 SO2

4 moles FeS2 ------------ 11 moles O2

26.62 moles FeS2 ------------ X

X = 26.62 moles FeS2 x 11 moles O2/4 moles FeS2

X = 73.20 moles

For 26.62 moles of FeS2, 73.20 moles of O2 are needed, but there are only 59.44 moles so the limiting reactant is O2, and the excess reactant is FeS2.

Answer:

The limiting reactant = O2

The excess reactant = FeS2

User Amin Ghaderi
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