Question

Given f(x) = 2x - 1 h(x) = x^2 + 1Find f[h(7)]

Answer 1

`f\lbrack h(7)\rbrack\text{ = 99}`

Step-by-step explanation:

Given the functions:

`\begin{gathered} f(x)=2x-1 \\ h(x)=x^2+1 \end{gathered}`

We want to find:

`f\lbrack h(7)\rbrack`

First of all, we need to find:

`f\lbrack h(x)\rbrack`

This is done by inserting the value of h(x) into f(x)

So, we have:

`\begin{gathered} f\lbrack h(x)\rbrack=2(x^2+1)-1 \\ =2x^2+2-1 \\ =2x^2+1 \end{gathered}`

Substituting 7 for x in f[h(x)], we have f[h(7)]

`\begin{gathered} f\lbrack h(7)\rbrack=2(7^2)+1 \\ =2(49)+1 \\ =98+1 \\ =99 \end{gathered}`

Which is what we are looking for.