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How many moles of sulfur are in a 707 gram sample of sulfur?

a) 12.2 moles of sulfur
Ob) 52.1 moles of sulfur
c) 51.1 moles of sulfur
od) 22.1 moles of sulfur

User LarryF
by
4.3k points

2 Answers

10 votes

Answer:


\boxed {\boxed {\sf D. \ 22.1 \ moles \ of \ sulfur}}

Step-by-step explanation:

To convert from moles to grams, we must use the molar mass. This can be found on the Periodic Table.

We are given a sample of sulfur. Look for the symbol S on the table.

  • Sulfur (S): 32.07 g/mol

This tells us the mass of 1 mole of sulfur. Use this molar mass as a ratio.


(32.07 \ g \ S)/(1 \ mol \ S )

Multiply by the given number of grams (707).


707 \ g \ S *(32.07 \ g \ S)/(1 \ mol \ S )

Flip the fraction so the grams of sulfur will cancel out.


707 \ g \ S *( 1 \ mol \ S )/(32.07 \ g \ S)


707 *( 1 \ mol \ S )/(32.07 )


( 707 \ mol \ S )/(32.07 )


22.0455254 \ mol \ S

The number we caluclated is the closest to answer choice D: 22.1 moles of sulfur

User Steve McKinney
by
4.6k points
4 votes

Answer:

d) 22.1 moles of sulfur

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table

Stoichiometry

  • Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

707 g S (Sulfur)

Step 2: Identify Conversions

Molar Mass of S - 32.07 g/mol

Step 3: Convert

  1. Set up:
    \displaystyle 707 \ g \ S((1 \ mol \ S)/(32.07 \ g \ S))
  2. Divide:
    \displaystyle 22.0455 \ mol \ S

Step 4: Round

Our closest answer is d) 22.1 moles of sulfur

This is due to dividing different rounded values.

User Mstdmstd
by
4.4k points