191k views
5 votes
How many moles of sulfur are in a 707 gram sample of sulfur?

a) 12.2 moles of sulfur
Ob) 52.1 moles of sulfur
c) 51.1 moles of sulfur
od) 22.1 moles of sulfur

User LarryF
by
7.9k points

2 Answers

10 votes

Answer:


\boxed {\boxed {\sf D. \ 22.1 \ moles \ of \ sulfur}}

Step-by-step explanation:

To convert from moles to grams, we must use the molar mass. This can be found on the Periodic Table.

We are given a sample of sulfur. Look for the symbol S on the table.

  • Sulfur (S): 32.07 g/mol

This tells us the mass of 1 mole of sulfur. Use this molar mass as a ratio.


(32.07 \ g \ S)/(1 \ mol \ S )

Multiply by the given number of grams (707).


707 \ g \ S *(32.07 \ g \ S)/(1 \ mol \ S )

Flip the fraction so the grams of sulfur will cancel out.


707 \ g \ S *( 1 \ mol \ S )/(32.07 \ g \ S)


707 *( 1 \ mol \ S )/(32.07 )


( 707 \ mol \ S )/(32.07 )


22.0455254 \ mol \ S

The number we caluclated is the closest to answer choice D: 22.1 moles of sulfur

User Steve McKinney
by
8.6k points
4 votes

Answer:

d) 22.1 moles of sulfur

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table

Stoichiometry

  • Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

707 g S (Sulfur)

Step 2: Identify Conversions

Molar Mass of S - 32.07 g/mol

Step 3: Convert

  1. Set up:
    \displaystyle 707 \ g \ S((1 \ mol \ S)/(32.07 \ g \ S))
  2. Divide:
    \displaystyle 22.0455 \ mol \ S

Step 4: Round

Our closest answer is d) 22.1 moles of sulfur

This is due to dividing different rounded values.

User Mstdmstd
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.