Answer:
220 g H₂O
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
Stoichiometry
- Using Dimensional Analysis
Step-by-step explanation:
Step 1: Define
12 moles H₂O (water)
Step 2: Identify Conversions
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
Step 3: Convert
- Set up:
![\displaystyle 12 \ moles \ H_2O((18.02 \ g \ H_2O)/(1 \ mol \ H_2O))](https://img.qammunity.org/2022/formulas/chemistry/high-school/vcg53lhxitqi2x834zrl2io99xku0zwysq.png)
- Multiply:
![\displaystyle 216.24 \ g \ H_2O](https://img.qammunity.org/2022/formulas/chemistry/high-school/ypmz5vljbiryokawnl0ufflt7fhz9lrh6r.png)
Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
216.24 g H₂O ≈ 220 g H₂O