Question

Isopropyl alcohol is mixed with water to produce 32.0% (v/v) alcohol solution.How many milliliters of each component are present in 655 mL of this solution? Assume the volumes are additive.Alcohol: _____________ mL Water: __________ mL

Answer 1

Isopropyl alcohol + water = Solution

Solute = Isopropyl alcohol

Solvent = water

% V/V = mL of solute / 100 ml of solution

Now we have 655 mL of solution.

32.0 % V/V means 32 mL of Isopropyl alcohol dissolved in 100 mL of solution.

So,

32 mL Isopropyl alcohol ------------------- 100 mL Solution

x ------------------- 655 mL Solution

x represents the volume of Isopropyl alcohol in 655 mL of solution

`x\text{ = }\frac{655\text{ mL solution x 32 mL }Isopropylalcohol\text{ }}{100\text{ mL solution}}=\text{ 209.6 mL of }Isopropylalcohol`

Now

Alcohol: 209.6 mL

Water: 655 mL (solution = Alcohol + Water) - 209.6 mL (alcohol) = 445.4 mL of water