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41 votes
Could someone pls help me out ???

Could someone pls help me out ???-example-1
User Vytautas
by
2.8k points

1 Answer

17 votes
17 votes

Answer:

Option C.

Explanation:


\sf\:x^(2)-3x+7=0

Use the biquadratic formula.


\sf\:\x=\frac{-\left(-3\right)(+/-)\sqrt{\left(-3\right)^(2)-4* 7}}{2}


\sf\:x=(-\left(-3\right)(+/-)√(9-4* 7))/(2)


\sf\:x=(-\left(-3\right)(+/-)√(9-28))/(2)


\sf\:x=(-\left(-3\right)(+/-)√(-19))/(2)


\sf\:x=(3(+/-)√(19))/(2)

Positive sign:


\boxed{\sf\:x=(3+√(19))/(2)}

Negative sign:


\boxed{\sf\:x=(3-√(19))/(2)}

Hope it helps ⚜

User H Sampat
by
3.1k points
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