Question

A fraction reduces to 36. If its denominator is 6x^5, what it's its numerator?

a) 6^3x
b) 6^3x^5
c) 6x^5
d) 6^7x^5

Answer 1

the answer is B because you will cancel the x^5 part on top and bottom and the numerator left 6^3 and denominator left 6
6^3=216divid by 6 you will get 36

Answer 2

Option (b) is correct.

Numerator is
`N=6^3x^5`.

Explanation:

Given : A fraction reduces to 36. If its denominator is
`6x^5`.

We have to find the numerator.

Let numerator be N.

and denominator =
`6x^5`.

Fraction (F) is numerator (N) over denominator(D).

`F=(N)/(D)`

Given : fraction is 36

`36=(N)/(6x^5)`

`6^2=(N)/(6x^5)`

Cross multiply , we get,

`(6^2)(6x^5)=N`

`N=6^3x^5`

Thus, numerator is
`N=6^3x^5`.

Option (b) is correct.