119k views
1 vote
A fraction reduces to 36. If its denominator is 6x^5, what it's its numerator?

a) 6^3x
b) 6^3x^5
c) 6x^5
d) 6^7x^5

User Shibu
by
8.3k points

2 Answers

1 vote
the answer is B because you will cancel the x^5 part on top and bottom and the numerator left 6^3 and denominator left 6
6^3=216divid by 6 you will get 36
User Edwin Cheong
by
7.6k points
4 votes

Answer:

Option (b) is correct.

Numerator is
N=6^3x^5.

Explanation:

Given : A fraction reduces to 36. If its denominator is
6x^5.

We have to find the numerator.

Let numerator be N.

and denominator =
6x^5.

Fraction (F) is numerator (N) over denominator(D).


F=(N)/(D)

Given : fraction is 36


36=(N)/(6x^5)


6^2=(N)/(6x^5)

Cross multiply , we get,


(6^2)(6x^5)=N


N=6^3x^5

Thus, numerator is
N=6^3x^5.

Option (b) is correct.

User GaspardP
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories