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What is the slope of a line that is perpendicular to the line y = -6x-5

User Hovo
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keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above


y = \stackrel{\stackrel{m}{\downarrow }}{-6}x-5\qquad \impliedby \begin{array} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill


\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{10em}} {\stackrel{slope}{-6\implies \cfrac{-6}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{-6}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{-6}\implies \cfrac{1}{6}}}

User Theraneman
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