Question

Please help, i'm horrible @ math :)

Answer 1

`\displaystyle\\ 1 (2)/(5) +\Big(-5 (1)/(2) \Big) = ? \\ \\ 1 (2)/(5) = (1* 5+2)/(5)=\boxed{(7)/(5)} \\ \\ -5 (1)/(2) =-5 -(1)/(2) = (-5*2-1)/(2) =(-10-1)/(2)=(-11)/(2)= \boxed{-(11)/(2) }\\ \\ \texttt{OR} \\ \\ -5 (1)/(2) = -\Big(5 (1)/(2) \Big)= -\Big( (5*2+1)/(2) \Big)=-\Big( (11)/(2) \Big)= \boxed{-(11)/(2) }`



`\displaystyle\\ \Longrightarrow ~~1 (2)/(5) +\Big(-5 (1)/(2) \Big) =(7)/(5) -(11)/(2) = (7* 2)/(5* 2) -(11* 5)/(2* 5) = \\ \\ = (14)/(10) -(55)/(10) = (14-55)/(10) =(-41)/(10) = -(41)/(10)=-(40+1)/(10)=\boxed{\boxed{-4(1)/(10)}}`