Question

Add.
(3t - 3) + (6t2 + 4t + 13) + (-8t2 + 11t - 1)?

Answer 1

The answer is -2t2 + 18t + 9

Answer 2

`=-2t^2+18t+9`

Explanation:

the expression we have is:

`(3t-3)+(6t^2+4t+13)+(-8t^2+11t-1)`

the first step is to get rid of the parentheses:

`3t-3+6t^2+4t+13-8t^2+11t-1`

an now, we put the like terms together, this will be subtract

`6t^2-8t^2`, and the result is
`-2t^2`

and then add:

`3t+4t+11t` which results in
`18t`

and finally add all the independent numbers:

`-3+13-1` which is equal to
`9`

so the total result is:

`(3t-3)+(6t^2+4t+13)+(-8t^2+11t-1)`
`=-2t^2+18t+9`