Question

Consider the complex number 2 = V17 (cos(104°) + i sin(104°)).Plot z in the complex plane below.If necessary, round the point's coordinates to the nearest integer.Im5+4+3+2+1 +ReA+-5+-4-3-2-112345-1+-2-3 +-4+-5 +

Answer 1

Recall that to plot a point in the complex plane we have to know its real part and its imaginary part.

The real part of the given number is

`\sqrt[]{17}\cos 104^(\circ),`

and its imaginary part is

`\sqrt[]{17}\sin 104^(\circ).`

Simplifying the above expressions, and rounding to the nearest integer we get that:

Therefore, the point has coordinates (-1,4).

Answer: