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Find the equation of the straight line that passes through the point (1,1/2) and has slope 1/2. Enter the equation in the point-slope form, y-...=...(x-...)

User Majida
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\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 1}}\quad ,&{{ (1)/(2)}})\quad % (c,d) \end{array} \\\quad \\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies\cfrac{1}{2} \\ \quad \\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad \begin{array}{llll} \textit{plug in the values}\\ \end{array}\\ \qquad \uparrow\\ \textit{point-slope form}
User Vatsal Shah
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