Question

What is the equation of the circle with center (-3.2,2.1) and radius 4.3?

Answer 1

`(x+3.2)^2+(y-2.1)^2=(4.3)^2`

Explanation:

It is given that the center of the circle is (-3.2,2.1) and radius is 4.3.

Now, the equation of the circle with center (a,b) and the radius 'r' is represented as:

`(x-a)^2+(y-b)^2=r^2`

Now, the given center is (-3.2,2.1) and radius is 4.3, thus the equation of the circle becomes,:

`(x-(-3.2))^2+(y-2.1)^2=(4.3)^2`

`(x+3.2)^2+(y-2.1)^2=(4.3)^2`

Which is the required equation.