Register
Factor 16x^2 + 16x + 4 completely a. (16x + 4)(x + 1) b. (4x + 2)(4x - 2) c. 4(2x + 1)^2
117k views
5 votes
Factor 16x^2 + 16x + 4 completely

a. (16x + 4)(x + 1)
b. (4x + 2)(4x - 2)
c. 4(2x + 1)^2

User Artem Luzhanovskyi
by
8.6k points

1 Answer

5 votes
16x^2 + 16x + 4...common factor is 4
4(4x^2 + 4x + 1) =
4(2x + 1)(2x + 1) =
4(2x + 1)^2 <===
User Natan Rubinstein
by
8.2k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Write words to match the expression. 24- ( 6+3)
Link Copied!