Question

How many moles are present in 0.23 kg of SO2

Answer 1

There are 3.594 moles of sulfur dioxide.

Step-by-step explanation:

`n=(m)/(M)`

n = moles of compound

m = mass of the compound

M = Molar mass of the compound

Mass of sulfur dioxide= m = 0.23 kg = 230 g (1 kg = 1000 g)\

Molar mass of sulfur dioxde = M = 64 g/mol

Moles of sulfur dioxide = n

`(230 g)/(64 g/mol)=3.594 mol`

There are 3.594 moles of sulfur dioxide.

Answer 2

Multiply first the mass given in kilograms by 1000 in order to convert it to grams.
(0.23 kg) (1000 g / 1kg) = 230 g
Then, divide the mass in gram by the molar mass of SO2
molar mass of SO2 = 64.044 g/mol
Solving for the number of moles,
(230 g)(1 mol/64.044g) = 3.59 moles
Thus, there are approximately 3.59 moles of SO2 present in 0.23 kg of SO2.