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Solve (x + 3)^2 + (x + 3) – 2 = 0. Let u = x+3 Rewrite the equation in terms of u. A. u^2 + u – 2 = 0 B. (u^2 + 9) + u – 2 = 0 C. u^2 + u + 1 = 0
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Solve (x + 3)^2 + (x + 3) – 2 = 0.

Let u = x+3
Rewrite the equation in terms of u.

A. u^2 + u – 2 = 0

B. (u^2 + 9) + u – 2 = 0

C. u^2 + u + 1 = 0

User Ronedg
by
5.5k points

2 Answers

4 votes

Answer:

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Explanation:

Solve (x + 3)^2 + (x + 3) – 2 = 0. Let u = x+3 Rewrite the equation in terms of u-example-1
User Shondeslitch
by
6.0k points
3 votes

Answer:

The answer is the option A


u^(2)+u-2=0

Explanation:

we have


(x+3)^(2)+(x+3)-2=0

Let


u=(x+3)

Substitute


(u)^(2)+(u)-2=0

User DoubleDunk
by
6.6k points
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