Question

Solve (x + 3)^2 + (x + 3) – 2 = 0.

Let u = x+3
Rewrite the equation in terms of u.

A. u^2 + u – 2 = 0

B. (u^2 + 9) + u – 2 = 0

C. u^2 + u + 1 = 0

Answer 1

<333333333333

Explanation:

Answer 2

The answer is the option A

`u^(2)+u-2=0`

Explanation:

we have

`(x+3)^(2)+(x+3)-2=0`

Let

`u=(x+3)`

Substitute

`(u)^(2)+(u)-2=0`