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16 votes
16 votes
Drag the tiles to the boxes to form correct pairs.Match each operation involving fx) and g(x) to its answer.(T) = 1 - 22 and g(x) = V11 – 40(gx )(2)(8 - 1)(-1)(9 + )(2)-373V3 - 30V15

User SeasonalShot
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1 Answer

19 votes
19 votes

1.


(g* f)(2)

It means multiply f(x) and g(x) and then put "2" into it. The solution is what we are looking for. So,


\begin{gathered} (g* f)(2)=\sqrt[]{11-4x}*1-x^2 \\ =\sqrt[]{11-4(2)}*1-(2)^2 \\ =\sqrt[]{3}*-3 \\ =-3\sqrt[]{3} \end{gathered}

2.


(g-f)(-1)

For this we subtract f from g and put -1 into the expression. So


\begin{gathered} (g-f)(-1)=\sqrt[]{11-4x}-1+x^2 \\ =\sqrt[]{11-4(-1)}-1+(-1)^2 \\ =\sqrt[]{15}-1+1 \\ =\sqrt[]{15} \end{gathered}

3.


(g+f)(2)

We simply add f and g and put 2 into the final expression.


\begin{gathered} (g+f)(2)=\sqrt[]{11-4x}+1-x^2 \\ =\sqrt[]{11-4(2)}+1-(2)^2 \\ =\sqrt[]{3}-3 \end{gathered}

4.


\begin{gathered} ((f)/(g))(-1) \\ \end{gathered}

We divide f by g and put -1 in the final expression. Shown below:


\begin{gathered} ((f)/(g))(-1)=\frac{1-x^2}{\sqrt[]{11-4x}} \\ =\frac{1-(-1)^2}{\sqrt[]{11-4(-1)}} \\ =\frac{0}{\sqrt[]{15}} \\ =0 \end{gathered}

Now, please match each answer with each choice.

User Yen
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