Question

Please do this step-by-step how do you do it when it’s between

Answer 1

Given:

• Mass of block A = 6.0 kg

,

• Mass of block B = 7.0 kg

,

• Mass of block C = 13.0 kg

,

• Force, F = 13.0 N

Let's find the magnitude of the tension in the rope between B and C.

Let's first find the acceleration.

We have:

`13-T_B+T_B-T_A+T_A=6a+7a+13a`

Thus, we have:

`\begin{gathered} 13=26a \\ \\ a=(13)/(26) \\ \\ a=0.5\text{ m/s}^2 \end{gathered}`

To find the tension between blocks B and C, we have the equation:

`\begin{gathered} F-T_B=M_C*a \\ \\ T_B=F-M_c*a \end{gathered}`

Where:

F = 13 N

Mc is the mass of block C = 13 kg

a is the acceleration = 0.5 m/s²

Thus, we have:

`\begin{gathered} T_B=13-13*0.5 \\ \\ T_B=13-6.5 \\ \\ T_B=6.5\text{ N} \end{gathered}`

Therefore, the magnitude of the tension in the rope between blocks B and C is 6.5 N

ANSWER:

6.5 N