Question

An inclined plane is set at an angle of 29 degrees above horizontalWhat is the acceleration of a 420 g block of ice sliding down the inclined plane? Assume no friction

Answer 1

The net force parallel to the plane is

∑ F = m g sin(29°) = m a

where

m = mass of the block

g = magnitude of the acceleration due to gravity, 9.8 m/s²

a = mag. of acceleration of the block

where we take the direction of the block's sliding down the plane to be positive. Then

a = g sin(29°) ≈ 4.8 m/s²