191k views
4 votes
What is the solution set of 7x^2+3x=0

User Malinosqui
by
7.9k points

2 Answers

1 vote
take the common 'x' out,

7x^2 +3x = 0
x (7x+3) = 0

so x = 0 or 7x+3 = 0
x=0 or 7x = -3
x=0 or x = -3/7

so the solutions are 0,-3/7.
User Claytog
by
7.8k points
0 votes

Answer:

x = 0 or x = -3/7

Explanation:

The equation is a second order polynnomial and would therefore have two solutions for x.

The solution of the set can be expressed as:


=7*x^2+3*x=0

The x is a common term in the expression so we can write is as:


=x*(7*x+3)=0

Where the expression is equal to zero the first solution of x is 0: x=0

The second part (7x+3) is also equal to zero and therefore:


7*x+3=0

After simplification x = -3/7

The solution of the set is x=0 or x=-3/7

Substituting either in the left hand side of the equation will make the whole equation equal to zero.

User Apostlion
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories