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How much heat energy is required to raise the temperature of 386 grams of aluminum from 24.0°C to 100.0°C?​

2 Answers

4 votes

Answer:

26.314KJ

Step-by-step explanation:

The specific heat capacity formula is :
Q=mcΔ
T, where Q is the heat energy, m is the mass, c is the heat capacity of the material, and delta T is the change in temperature.

We know from the question that m = 386grams and delta T = 100.0°C - 24.0°C = 76.0°C. From a simple search, we know the specific heat capacity of aluminum = 0.897J/g°C (this changes a little bit depends on the website you use, but the value should be very similar). Let's apply the formula:


Q=mcΔ
T


Q = 386g (0.897J/gC)(76.0C)


Q = 26314J or
26.314KJ

Round according to your teacher's specification (example: significant figures) if needed.

User Amr El Aswar
by
3.7k points
3 votes

Answer:

is there no options?

Step-by-step explanation:

User Ramazan Murat
by
3.4k points