Answer:
B. x = 3
C. Segment AT = 7
F. Segment AL = 22
Explanation:
To figure out what the length of Segments AT and AL are use the equation ((2x + 1) + 15) = 7x + 1.
((2x + 1) + 15) = 7x + 1
Add 1 to 15 to get 16.
2x + 16 = 7x + 1
Subtract 7x from both sides. This cancels the +7x.
2x + 16 - 7x = 1
Combine 2x and -7x to get -5x
-5x + 16 = 1
Subtract 16 from both sides. This chancels the +16x.
-5x = 1 - 16
Subtract 16 from 1 to get -15.
-5x = -15
Divide both sides by -5. This cancels the multiplication by -5.
x = -15/-5
Dividing any two negative numbers ends in a positive. Divide -15 by -5 to get 3.
x = 3
Now, substitute x for 3 in 2x + 1 and 7x + 1 to figure out the lengths.
2(3) + 1
Mulitply 2 by 3 for 6.
6 + 1
Add 1 to 6 to get 7.
Segment AT is 7 units long.
7(3) + 1
Multiply 7 by 3 to get 21.
21 + 1
Add 1 to 21 to get 22.
Segment AL is 22 units long.