Answer:
csc angle C equals 3 over 2
Explanation:
In this problem
The hypotenuse is BC (greater side)
The legs are AC and AB
we know that

----> opposite side of angle C divided by the hypotenuse
therefore

substitute the given values

Simplify

Note In this problem, the ABC triangle cannot be a right triangle, since its measurements do not satisfy the Pythagoras theorem, so I assume that it must be a problem created for didactic purposes