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3 votes
Find the product.

(n 3) 3 · (n 4) 5

N

User Nate Barr
by
8.6k points

2 Answers

3 votes

(n^3)^3 · (n^4)^5

=n^9 · n^20

=n^29

User Andrea Sessa
by
8.0k points
1 vote

Answer:


(n^(29).

Explanation:

Given :
(n^(3))^(3) * (n^(4))^(5).

To find : Find the product.

Solution : We have given that


(n^(3))^(3) * (n^(4))^(5).

By the exponent rule 1 )
(x^(a))^(b) = x^(ab).

Same base rule 2)
x^(a)* x^(b) = x^(a +b).

Then ,


(n^(3))^(3) * (n^(4))^(5) =
(n^(9)* (n^(20).

Now, by rule 2.


(n^(3))^(3) * (n^(4))^(5) =
(n^(29).

Therefore,
(n^(29).

User Spielbug
by
8.6k points

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