Question

Find the product.

(n 3) 3 · (n 4) 5

N

Answer 1

(n^3)^3 · (n^4)^5

=n^9 · n^20

=n^29

Answer 2

`(n^(29)`.

Explanation:

Given :
`(n^(3))^(3) * (n^(4))^(5)`.

To find : Find the product.

Solution : We have given that

`(n^(3))^(3) * (n^(4))^(5)`.

By the exponent rule 1 )
`(x^(a))^(b) = x^(ab)`.

Same base rule 2)
`x^(a)* x^(b) = x^(a +b)`.

Then ,

`(n^(3))^(3) * (n^(4))^(5)` =
`(n^(9)* (n^(20)`.

Now, by rule 2.

`(n^(3))^(3) * (n^(4))^(5)` =
`(n^(29)`.

Therefore,
`(n^(29)`.