Solve each linear-quadratic system algebraically

Question

asked Apr 27, 2018 76.8k views

1 Answer

SHANib · Answer 1 · 2018-05-02T23:27:21+0000

For the first one, Y-5=(x-2)^2. First you multiply x-2•X-2, which is x^2-4x+4. Lastly, you subtract -5 from both sides so the equation would look like Y=x^2-4x+9.

Solve each linear-quadratic system algebraically

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

No related questions found

Categories

Other Questions