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Cal the molarity of solution prepared by dissolving 250 of Ca(NO3)2 to make 2.5L of solution
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Dec 8, 2018
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Cal the molarity of solution prepared by dissolving 250 of Ca(NO3)2 to make 2.5L of solution
Chemistry
high-school
SergioLucas
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Molar mass Ca(NO3)2 =
164.088 g/mol
number of moles:
250 / 164.088 => 1.523 moles
Volume = 2.5 L
Therefore:
Molarity = moles / Volume
Molarity = 1.523 / 2.5
=>
0.6092 M
Rcgldr
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Dec 15, 2018
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Rcgldr
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