20.3k views
1 vote
(cosx/secx-1)-(cosx/tan^2x)=cot^2x

User NevilleDNZ
by
8.4k points

1 Answer

4 votes
cos(x)(sec(x)+1_/((sec(x))^2-1)
(1+cos(x))/(tan(x))^2 as (sec(x))^2-1=(tan(x))^2
so cos(x)/(sec(x)-1)-(cos(x)/(tan(x)^2)=(1+cos(x)/((tan(x)^2)-(cos(x)/(tan(x))^2)=1/(tan(x))^2=(cot(x))^2
User Volkersfreunde
by
9.1k points

Related questions

1 answer
2 votes
141k views
asked Dec 18, 2024 79.1k views
Nerve asked Dec 18, 2024
by Nerve
7.6k points
1 answer
0 votes
79.1k views